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вертикальный
sustraer

Oxford Spanish Dictionary

Angleščina
Angleščina
Španščina
Španščina

I. subtract [am. angl. səbˈtrækt, brit. angl. səbˈtrakt] GLAG. preh. glag.

subtract
to subtract sth from sth
subtract X from Y
subtract X from Y

II. subtract [am. angl. səbˈtrækt, brit. angl. səbˈtrakt] GLAG. nepreh. glag.

subtract
Španščina
Španščina
Angleščina
Angleščina
I can't subtract
restar número
to subtract
to subtract sth from sth
restar 15 de 36
subtract 15 from 36
to subtract
to subtract

v slovarju PONS

Angleščina
Angleščina
Španščina
Španščina

subtract [səbˈtrækt] GLAG. preh. glag.

subtract
to subtract 3 from 5
restar 3 a 5
Španščina
Španščina
Angleščina
Angleščina
to subtract
to subtract
to subtract
v slovarju PONS
Angleščina
Angleščina
Španščina
Španščina

subtract [səb·ˈtrækt] GLAG. preh. glag.

subtract
to subtract 3 from 5
restar 3 a 5
Španščina
Španščina
Angleščina
Angleščina
to subtract
to subtract
to subtract
Present
Isubtract
yousubtract
he/she/itsubtracts
wesubtract
yousubtract
theysubtract
Past
Isubtracted
yousubtracted
he/she/itsubtracted
wesubtracted
yousubtracted
theysubtracted
Present Perfect
Ihavesubtracted
youhavesubtracted
he/she/ithassubtracted
wehavesubtracted
youhavesubtracted
theyhavesubtracted
Past Perfect
Ihadsubtracted
youhadsubtracted
he/she/ithadsubtracted
wehadsubtracted
youhadsubtracted
theyhadsubtracted

PONS OpenDict

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Primeri iz slovarja PONS (uredniško pregledani)

to subtract 3 from 5
restar 3 a 5

Enojezični primeri (nepregledani od uredništva PONS)

In case 1, operand 1 is 0 so the result is produced simply by subtracting 1 from 1 at every bit position.
en.wikipedia.org
A point is subtracted for each word that contains one or more mistakes, including missing or extra words.
en.wikipedia.org
The internal electronic circuitry of an active noise-canceling mic attempts to subtract noise signal from the primary microphone.
en.wikipedia.org
In lower genus, one must account for the presence of smooth families of automorphisms, by subtracting their number.
en.wikipedia.org
It turns out that adding and subtracting constants is the only flexibility we have in finding different antiderivatives of the same function.
en.wikipedia.org